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AQA GCSE Chemistry
Revision NotesUsing Avogadro’s Law (Higher Tier)
Using Avogadro’s Law (Higher Tier)
Avogadro's Law Basics
Avogadro’s Law states that equal volumes of gases, at the same temperature and pressure, contain the same number of particles (moles). This means that the volume of a gas is directly proportional to the amount (in moles) of gas present, provided the temperature and pressure remain constant.
Mathematically, this can be expressed as:
where is the volume of the gas and is the number of moles.
This relationship is fundamental in understanding how gases behave and is only valid when temperature and pressure are constant. Changing temperature or pressure affects gas volume independently of the amount of gas.
For instance, if you have 2 moles of a gas at constant temperature and pressure, the volume will be twice that of 1 mole of the same gas under the same conditions.
- Remember: "Equal volumes, equal moles" at constant temperature and pressure.
- Temperature and pressure must be kept constant for Avogadro’s Law to apply.
Using Avogadro's Law in Calculations
At room temperature and pressure (RTP), one mole of any gas occupies approximately 24 dm³. This is a key value for calculations involving gases and moles.
You can calculate the number of moles from a given volume of gas using:
where is the number of moles and is the volume in dm³.
Conversely, to find the volume of gas from the number of moles:
This is useful for predicting gas volumes in reactions and for converting between moles and volumes.
For example, if you have 3 moles of a gas at RTP, the volume is:
Worked Example
Example: Calculate the number of moles in 48 dm³ of oxygen gas at RTP.
Worked Example
Example: Find the volume of 0.5 moles of nitrogen gas at RTP.
Applications of Avogadro's Law
Avogadro’s Law helps predict volumes of gases involved in chemical reactions when the gases are measured at the same temperature and pressure.
For example, the volumes of reacting gases and products can be related directly to the moles shown in a balanced chemical equation. This is because equal moles of gases occupy equal volumes at RTP.
If a balanced equation shows 1 mole of gas A reacts with 2 moles of gas B, then at RTP, 1 volume of gas A reacts with 2 volumes of gas B.
This relationship allows you to:
- Predict volumes of gases consumed or produced in reactions.
- Compare volumes of gases using mole ratios from balanced equations.
- Understand gas stoichiometry without needing to convert to mass.
For instance, in the reaction:
2 moles of hydrogen gas react with 1 mole of oxygen gas. At RTP, this means 2 volumes of hydrogen react with 1 volume of oxygen.
So, if you start with 6 dm³ of hydrogen, you would need 3 dm³ of oxygen for complete reaction.
This direct volume relationship simplifies calculations involving gases in reactions.
Worked Example
Example: In the reaction between hydrogen and oxygen to form water vapour, how many dm³ of oxygen are needed to react completely with 12 dm³ of hydrogen at RTP?
Worked Example
Example: A reaction produces 15 dm³ of carbon dioxide gas at RTP. According to the balanced equation, 1 mole of reactant produces 1 mole of CO₂. How many moles of reactant were used?
- Use volume ratios from balanced equations directly for gases at RTP.
- Always check temperature and pressure conditions before applying Avogadro’s Law.
- Remember 24 dm³ per mole is an approximate value at RTP, suitable for GCSE calculations.
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