Topic navigation panel

Topic navigation panel

AQA GCSE Chemistry

Revision Notes
(Concentration of Solutions)

Titration Basics (Higher Tier Overview)

Titration Basics (Higher Tier Overview)

Purpose of Titration

Titration is a laboratory method used to find the concentration of an unknown solution by reacting it with a solution of known concentration (called the standard solution or titrant). It relies on an acid-base neutralisation reaction where the acid and alkali react to form water and a salt.

An indicator is added to the unknown solution to show the end point of the titration. The end point is the moment when the acid and alkali have completely reacted, indicated by a permanent colour change.

The main goal is to measure accurately how much titrant is needed to neutralise the unknown solution, which then allows calculation of the unknown concentration.

Common indicators include phenolphthalein, which changes from colourless in acid to pink in alkali, and methyl orange, which changes from red in acid to yellow in alkali. These indicators are chosen because their colour change occurs close to the equivalence point of the titration.

Equipment and Setup

  • Burette: A long, graduated glass tube with a tap at the bottom, used to add the titrant dropwise to the unknown solution. It allows precise measurement of the volume added.
  • Pipette: Used to measure a fixed volume of the unknown solution accurately and transfer it to the conical flask.
  • Conical Flask: The flask where the unknown solution and indicator are mixed. Its shape helps prevent splashing during swirling.
  • White Tile: Placed under the conical flask to make the colour change of the indicator easier to see clearly.

Procedure Steps

  1. Rinse the burette with the standard solution (titrant) and then fill it, ensuring no air bubbles are present. Record the initial volume.
  2. Use a pipette to measure a precise volume of the unknown solution and transfer it to the conical flask.
  3. Add a few drops of a suitable indicator to the unknown solution in the flask. Common indicators include phenolphthalein (pink in alkali, colourless in acid) or methyl orange (red in acid, yellow in alkali).
  4. Slowly add the titrant from the burette to the flask, swirling the flask continuously to mix.
  5. Stop adding titrant as soon as the indicator changes colour permanently, signalling the end point.
  6. Record the final volume of titrant in the burette and calculate the volume used by subtracting the initial volume.

For example, if the initial burette reading is 0.00 cm³ and the final reading is 23.45 cm³, the volume of titrant used is:

Volume of titrant=23.450.00=23.45 cm3\text{Volume of titrant} = 23.45 - 0.00 = 23.45 \text{ cm}^3

  • Always rinse the burette and pipette with the solutions they will contain to avoid contamination.
  • Swirl the conical flask continuously during titration to mix the solutions thoroughly.
  • Use a white tile under the flask to help spot the colour change clearly.

Calculations

The key to titration calculations is using the volumes measured and the balanced chemical equation to find the unknown concentration.

Steps for calculation:

  • Read burette volumes accurately: Always record initial and final readings to find the volume of titrant used.
  • Calculate the volume of titrant used: Subtract initial from final volume.
  • Use the balanced chemical equation: Determine the mole ratio between the titrant and the unknown solution.
  • Calculate moles of titrant used: Use the concentration and volume of the titrant.
  • Calculate moles of unknown solution: Use the mole ratio from the balanced equation.
  • Calculate the concentration of the unknown: Use the moles and volume of the unknown solution.

For example, if 25.0 cm³ of an acid is neutralised by 23.45 cm³ of 0.100 mol/dm³ sodium hydroxide (NaOH), the moles of NaOH used are:

Moles of NaOH=concentration×volume (dm3)=0.100×23.451000=0.002345 mol\text{Moles of NaOH} = \text{concentration} \times \text{volume (dm}^3) = 0.100 \times \frac{23.45}{1000} = 0.002345 \text{ mol}

If the balanced equation is:

HCl+NaOHNaCl+H2O\text{HCl} + \text{NaOH} \rightarrow \text{NaCl} + \text{H}_2\text{O}

The mole ratio of HCl to NaOH is 1:1, so moles of HCl = 0.002345 mol.

Then, the concentration of HCl is:

Concentration of HCl=molesvolume (dm3)=0.00234525.0/1000=0.0938 mol/dm3\text{Concentration of HCl} = \frac{\text{moles}}{\text{volume (dm}^3)} = \frac{0.002345}{25.0/1000} = 0.0938 \text{ mol/dm}^3

PracticeExample 4

Worked Example

Example: 30.0 cm³ of hydrochloric acid is neutralised by 28.5 cm³ of 0.150 mol/dm³ sodium hydroxide. Calculate the concentration of the acid.

PracticeExample 5

Worked Example

Example: 25.0 cm³ of sulfuric acid (H₂SO₄) is neutralised by 30.0 cm³ of 0.200 mol/dm³ sodium hydroxide. Calculate the concentration of the sulfuric acid.

PracticeExample 6

Worked Example

Example: 50.0 cm³ of an unknown alkali is neutralised by 40.0 cm³ of 0.250 mol/dm³ hydrochloric acid. Calculate the concentration of the alkali.

Example calculation inline: Calculate the moles of 0.100 mol/dm³ NaOH used if 25.0 cm³ is added during titration.

Moles of NaOH=0.100×25.01000=0.0025 mol\text{Moles of NaOH} = 0.100 \times \frac{25.0}{1000} = 0.0025 \text{ mol}

  • Always write and balance the chemical equation before starting calculations.
  • Convert all volumes from cm³ to dm³ by dividing by 1000 before using in calculations.
  • Ensure units are consistent: concentration in mol/dm³, volume in dm³, moles in mol.
  • Read the burette carefully to the nearest 0.05 cm³ for accuracy.

Quick actions

Press Enter to send, Shift+Enter for new line

Choose Your Study Plan

MonthlyAnnualSave 20%

Plus

£4.99/month
  • Everything in Free plus...
  • Unlimited revision resources access
  • AI assistance (Within usage limits)
  • Enhanced progress tracking
  • New features soon...

Pro

£9.99/month
  • Everything in Plus plus...
  • Unlimited AI assistance
  • Unlimited questions marked
  • Detailed feedback and explanations
  • Comprehensive progress tracking
  • New features soon...
Most Popular