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AQA GCSE Chemistry

Revision Notes
(Measurement, Mass & Equations)

Limiting Reactants (Higher Tier)

Limiting Reactants (Higher Tier)

Concept of Limiting Reactants

In a chemical reaction, the limiting reactant is the substance that is completely used up first. Once this reactant runs out, the reaction stops because there is no more of it to react. This limits the amount of product that can be formed.

Other reactants that are not completely used up are said to be in excess. They remain after the reaction has finished because there was more than enough to react with the limiting reactant.

Identifying the limiting reactant is important because it determines the maximum amount of product that can be made in a reaction.

For example, if you react hydrogen with oxygen to make water:

If hydrogen runs out before oxygen, hydrogen is the limiting reactant, and the amount of water formed depends on how much hydrogen was available.

Calculations with Limiting Reactants

To solve limiting reactant problems, you must:

  • Use a balanced chemical equation to find the mole ratio between reactants and products.
  • Calculate the number of moles of each reactant you have.
  • Compare the mole ratio of reactants you have with the ratio required by the balanced equation.
  • Identify which reactant is limiting (the one that produces the least amount of product).
  • Calculate the theoretical yield of product based on the limiting reactant.

The key is to compare the actual mole ratio of reactants with the ratio required by the equation. The reactant that is short of what is needed is the limiting reactant.

For instance, consider the reaction:

N2+3H22NH3\text{N}_2 + 3\text{H}_2 \rightarrow 2\text{NH}_3

If you have 1 mole of nitrogen and 3 moles of hydrogen, the mole ratio is exactly right (1:3), so neither reactant is in excess and both are completely used up.

If you have 1 mole of nitrogen but only 2 moles of hydrogen, hydrogen is limiting because you need 3 moles of hydrogen for every mole of nitrogen, but only have 2 moles.

Once the limiting reactant is identified, use its moles and the balanced equation to calculate the moles of product formed, then convert to mass if needed using relative formula mass (Mr).

For example, if 0.5 moles of limiting reactant produce 1 mole of product, then 0.5 moles of product are formed.

Learning example:

In the reaction:

2Mg+O22MgO\text{2Mg} + \text{O}_2 \rightarrow 2\text{MgO}

Suppose you have 4 moles of magnesium and 1 mole of oxygen. Which is limiting?

Balanced equation ratio: 2 moles Mg react with 1 mole O₂.

Actual ratio: 4 moles Mg : 1 mole O₂ = 4:1.

Required ratio is 2:1, but actual Mg is in excess (4 > 2), so oxygen is limiting.

The amount of MgO formed depends on oxygen moles:

From the equation, 1 mole O₂ produces 2 moles MgO, so 1 mole O₂ produces 2 moles MgO.

  • Always start by writing a balanced equation before any calculation.
  • Compare mole ratios, not just amounts in grams or masses.
  • Limiting reactant determines maximum product formed; excess reactant remains unreacted.
PracticeExample 3

Worked Example

Example: In the reaction N2+3H22NH3\text{N}_2 + 3\text{H}_2 \rightarrow 2\text{NH}_3, you have 2 moles of nitrogen and 5 moles of hydrogen. Identify the limiting reactant and calculate the moles of ammonia formed.

Practical Applications

Understanding limiting reactants helps predict how much product can be made in real reactions, which is essential in both laboratory and industrial settings.

  • Predicting product amounts: Knowing which reactant limits the reaction allows chemists to calculate the maximum possible yield.
  • Explaining incomplete reactions: Sometimes reactions stop before all reactants are used because one reactant runs out first.
  • Industrial processes: Industries often use an excess of one reactant to ensure the other reactant is completely used, maximising product formation and minimising waste.

For example, in the Haber process for ammonia production, nitrogen and hydrogen react. Hydrogen is often supplied in excess to ensure all nitrogen reacts, improving efficiency.

PracticeExample 5

Worked Example

Example: In the reaction 2H2+O22H2O\text{2H}_2 + \text{O}_2 \rightarrow 2\text{H}_2\text{O}, 10 moles of hydrogen react with 4 moles of oxygen. Identify the limiting reactant and calculate the moles of water formed.

PracticeExample 6

Worked Example

Example: A reaction between 5 moles of calcium and 3 moles of chlorine gas produces calcium chloride according to:

Ca+Cl2CaCl2\text{Ca} + \text{Cl}_2 \rightarrow \text{CaCl}_2

Identify the limiting reactant and calculate the moles of calcium chloride formed.

  • In industrial reactions, supplying one reactant in excess ensures complete use of the other, improving efficiency.
  • Limiting reactant calculations help chemists minimise waste and cost by optimising reactant quantities.
  • Always check mole ratios carefully; incorrect identification of limiting reactant leads to wrong product predictions.

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