AQA GCSE Maths

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(Linear Equations)

Solving Linear Equations

Understanding Solving Linear Equations

What Are Linear Equations?

A linear equation is an equation where the highest power of the variable (e.g., xx) is 1. It forms a straight line when plotted on a graph, but for now, we’re focusing on solving them step by step.

Think of solving an equation as balancing a set of scales: whatever you do to one side, you must do to the other side to keep the balance

 

How to Solve Linear Equations

Key Steps:

  1. Simplify both sides: Expand any brackets and combine like terms.
  2. Collect the variable to one side: Make sure all occurrences of the variable are collected on one side 
  3. Isolate the variable: Use addition, subtraction, multiplication, or division (BIDMAS) to get the variable by itself.
  4. Check your solution: Substitute your solution back into the original equation to see if it works.

 

Tip

When rearranging you can 'move' variables from one side to the other by applying the opposite operation to both sides, i.e 2x11=13To ’move’ the 11 from the left hand side of the equation// I can do the opposite by adding 11 to both sidesthis cancels out the -11 on the left and adds it to the right to give2x11+11= 13+112x=242x - 11 = 13 \\ \text{To 'move' the 11 from the left hand side of the equation} // \text{ I can do the opposite by adding 11 to both sides} \\ \text{this cancels out the -11 on the left and adds it to the right to give} \\ 2x - 11 + 11 =  13 + 11 \\ 2x = 24

 

Examples

Example 1: Solve 3x+5=203x + 5 = 20

Step 1: Subtract 5 from both sides to remove the constant: 3x+55=205 3x=153x + 5 - 5 = 20 - 5 \\  3x = 15

Step 2: Divide both sides by 3 to isolate xx: x=153  x=5x = \frac{15}{3}  \\  x = 5

Check: Substitute x=5x = 5 into the original equation: 3(5)+5=203(5) + 5 = 20

 

solving linear equation example

 

Example 2: Solve 2x+3 =7x122x + 3  = 7x - 12

Step 1: Subtract 2x2x from both sides to move all xx-terms to one side: 2x2x+3=7x2x12 3=5x122x - 2x + 3 = 7x - 2x - 12  \\ 3 = 5x - 12

Step 2: Add 12 to both sides to remove the constant from the right: 3+12=5x12+1215=5x3 + 12 = 5x - 12 + 12 \\ 15 = 5x

Step 3: Divide both sides by 5: x=155 x=3x = \frac{15}{5}  \\ x = 3

Check: Substitute x=3x = 3 into the original equation: 2(3)+3=7(3)126+3=2112 9=92(3) + 3 = 7(3) - 12 \\ 6 + 3 = 21 -12  \\ 9 = 9

 

 

Worked Example

Worked Example

Solve 4x+6=10x184x + 6 = 10x - 18

 

 

 

 

Examples: Solving Complex Linear Equations

Example 3: Solve 5(x3)+2= 3(2x+1)45(x - 3) + 2 =  3(2x + 1) -4

Step 1: Expand the brackets 5x15+2=6x+34Simplify both sides: 5x13=6x15x - 15 + 2 = 6x + 3 -4 \\ \text{Simplify both sides:}  \\ 5x - 13 = 6x -1

Step 2: Move all xx-terms to one side. Subtract 5x5x from both sides: 13=x1-13 = x -1

Step 3: Move constants to the other side. Add 1 to both sides: 12=x-12 = x

Solution: x=12x = -12

 

 

Worked Example

Worked Example

Solve 5(x+2)3=2(x4)+75(x + 2) - 3 = 2(x - 4) + 7

 

 

 

 

 

Example 3: Solve 2x+53=x12+1\frac{2x+5}{3} = \frac{x -1}{2} + 1

Step 1: Eliminate fractions by multiplying through by the lowest common denominator (LCD), which is 6: 6×2x+53=6×x12+6×1Simplify each term: 2(2x+5)=3(x1)+66 \times \frac{2x + 5}{3} = 6 \times \frac{x -1}{2} + 6 \times 1 \\ \text{Simplify each term:}  \\ 2(2x + 5) = 3(x -1) + 6

Step 2: Expand the brackets. 4x+10= 3x3+6Simplify both sides: 4x+10=3x+34x + 10 =  3x -3 + 6 \\ \text{Simplify both sides: } \\ 4x + 10 = 3x + 3

Step 3: Move xx-terms to one side and constants to the other. Subtract 3x3x from both sides: x+10=3Subtract 10 from both sides:x=7x + 10 = 3 \\ \text{Subtract 10 from both sides:} \\ x = -7

Solution: x=7x = -7

 

 

Worked Example

Worked Example

Solve 3x+7=x+52+x343x + 7 = \frac{x+5}{2} + \frac{x - 3}{4}:

 

 

Tuity Tip

Hover me!

Balance the Equation: Always do the same thing to both sides.

Eliminate Fractions First: Multiply through by the denominator.

Combine Like Terms: Simplify each side before solving.

Check Your Answer: Substitute back into the original equation to confirm.

 

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