AQA GCSE Maths

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(Circle Theorems)

Circle Theorems: Cyclic Quadrilaterals

Circle Theorems: Cyclic Quadrilaterals

 

What Is a Cyclic Quadrilateral?

A cyclic quadrilateral is a four-sided shape where all the vertices lie on the circumference of a circle.

If a quadrilateral is cyclic, then a special rule applies:

Opposite angles add up to 180°\text{Opposite angles add up to } 180\degree

This is one of the most useful theorems when working with circle geometry.

 

diagram of cyclic quadrilateral theorem

 

Key Facts

Opposite angles in a cyclic quadrilateral always add up to 180°180\degree.

Only works when all corners lie on the circle.

This property does not apply if one corner is inside or outside the circle.

 

How to Spot a Cyclic Quadrilateral

Look for a four-sided shape where every corner is on the edge of the circle. These shapes often look like a kite, trapezium or square that fits perfectly inside the circle.

If you're not sure, check the points — are they all on the circumference?

 

 

Tuity Tip

Hover me!

If you're given a quadrilateral and you see opposite angles labelled, try adding them together. If they add up to 180°180\degree, you’re probably working with a cyclic quadrilateral 

 

 

Example

Question:

In a cyclic quadrilateral, one angle is 72°72\degree. What is the size of the opposite angle?

 
Answer:

Opposite angles in a cyclic quadrilateral add to 180°\text{Opposite angles in a cyclic quadrilateral add to } 180\degree

180°72°=108°180\degree - 72\degree = 108\degree

So the opposite angle is: 108°\boxed{108\degree}

 

Worked Example

Question:

In the diagram below, points A,B,C,DA, B, C, D lie on the circumference of a circle. The quadrilateral ABCDABCD is cyclic.

You're told:

DAB=2x+4\angle DAB = 2x + 4

BCD=20°\angle BCD = 20\degree

DCB=18°\angle DCB = 18\degree

Find the value of xx.

 
Step 1: Use Triangle Rules

In triangle DCBDCB, angles must add up to 180°180\degree. You’re given:

BCD=20°\angle BCD = 20\degree

DCB=18°\angle DCB = 18\degree

CBD=180°20°18°=142°\angle CBD = 180\degree - 20\degree - 18\degree = 142\degree

But since this isn't part of the cyclic pair, we look to the quadrilateral.

 

Step 2: Use the Cyclic Quadrilateral Theorem

DAB+BCD=180°\angle DAB + \angle BCD = 180\degree

Substitute the given values: (2x+4)+(20+18)=180(2x + 4) + (20 + 18) = 180

2x+4+38=1802x+42=1802x=138x=692x + 4 + 38 = 180 \to \quad 2x + 42 = 180 \to \quad 2x = 138 \Rightarrow x = 69

Final Answer:

x=69°\boxed{x = 69\degree}

 

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