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AQA GCSE Maths

Revision Notes
(Pythagoras & Trigonometry)

Pythagoras' Theorem

Pythagoras' Theorem

Pythagoras who?

  • Pythagoras was an ancient Greek mathematician who lived over 2500 years ago. 
  • He is best known for discovering the Pythagorean Theorem, which is one of the fundamental principles in geometry, used for finding missing side lengths in right-angled triangles.

 
Pythagoras' Theorem Explained

Pythagoras' Theorem states that in any right-angled triangle

  • The square of the hypotenuse (longest side) is equal to the sum of the squares of the other two sides:

a2+b2=c2a^2 + b^2 = c^2

 

Pythagoras' theorem diagram with equation

 

where:

  • c is the hypotenuse (the side opposite the right angle and the longest side)
  • a and b are the two shorter sides

Key Note: It does not matter which of the two shorter sides is labeled as a or b, but c must always be the hypotenuse

 

Finding the Hypotenuse

If you need to find the hypotenuse (c):

  1. Square the lengths of both shorter sides.
  2. Add these squared values.
  3. Take the square root to find c.

c=a2+b2c = \sqrt{a^2 + b^2}

 

Example: Finding the Hypotenuse

A right-angled triangle has sides of 6 cm and 8 cm. Find the hypotenuse.

Final Answer: The hypotenuse is 10 cm.

 

Finding a Shorter Side

If you need to find one of the shorter sides:

  1. Square the lengths of the hypotenuse and the known shorter side.
  2. Subtract these squared values.
  3. Take the square root to find the missing side.

a=c2b2a = \sqrt{c^2 - b^2}

 

Example: Finding a Shorter Side

A right-angled triangle has a hypotenuse of 13 cm and one shorter side of 5 cm. Find the missing side.

a=13252 a=16925  a=144 a=12a = \sqrt{13^2 - 5^2} \quad  a = \sqrt{169 - 25}  \\  a = \sqrt{144} \quad  a = 12

Final Answer: The missing side is 12 cm.

 

 

Always check which side is the hypotenuse. It must be the longest side and is always opposite the right angle.

Double-check subtraction. When finding a shorter side, subtract correctly to avoid negative numbers (which result in errors when taking square roots).

Leave answers in exact form if required. If a question asks for an exact value, leave your answer as a square root (e.g., 50\sqrt{50} ) instead of a decimal approximation.

Round only at the final step. If the answer needs to be rounded to a certain number of decimal places, only round at the very end to avoid inaccuracies.

PracticeExample 3

Worked Example

Problem: In the diagram below:

 

diagram of two triangles

AB=14cmAB = 14 \text{cm}

AC=24cmAC = 24 \text{cm}

AD=10cmAD = 10 \text{cm}

Find BCBC to 1 decimal place.

 

 

 

 

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