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AQA GCSE Maths
Revision NotesPythagoras' Theorem
Pythagoras' Theorem
Pythagoras who?
- Pythagoras was an ancient Greek mathematician who lived over 2500 years ago.
- He is best known for discovering the Pythagorean Theorem, which is one of the fundamental principles in geometry, used for finding missing side lengths in right-angled triangles.
Pythagoras' Theorem Explained
Pythagoras' Theorem states that in any right-angled triangle
- The square of the hypotenuse (longest side) is equal to the sum of the squares of the other two sides:
where:
- c is the hypotenuse (the side opposite the right angle and the longest side)
- a and b are the two shorter sides
Key Note: It does not matter which of the two shorter sides is labeled as a or b, but c must always be the hypotenuse
Finding the Hypotenuse
If you need to find the hypotenuse (c):
- Square the lengths of both shorter sides.
- Add these squared values.
- Take the square root to find c.
Example: Finding the Hypotenuse
A right-angled triangle has sides of 6 cm and 8 cm. Find the hypotenuse.
Final Answer: The hypotenuse is 10 cm.
Finding a Shorter Side
If you need to find one of the shorter sides:
- Square the lengths of the hypotenuse and the known shorter side.
- Subtract these squared values.
- Take the square root to find the missing side.
Example: Finding a Shorter Side
A right-angled triangle has a hypotenuse of 13 cm and one shorter side of 5 cm. Find the missing side.
Final Answer: The missing side is 12 cm.
Always check which side is the hypotenuse. It must be the longest side and is always opposite the right angle.
Double-check subtraction. When finding a shorter side, subtract correctly to avoid negative numbers (which result in errors when taking square roots).
Leave answers in exact form if required. If a question asks for an exact value, leave your answer as a square root (e.g., ) instead of a decimal approximation.
Round only at the final step. If the answer needs to be rounded to a certain number of decimal places, only round at the very end to avoid inaccuracies.
Worked Example
Problem: In the diagram below:
Find to 1 decimal place.
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