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AQA GCSE Physics

Revision Notes
(Forces & Elasticity)

Work Done on a Spring

Work Done on a Spring

Work Done on a Spring

Work done is the energy transferred when a force moves an object through a distance. When you stretch or compress a spring, work is done on the spring by the applied force.

This work done is stored as elastic potential energy in the spring. The more you stretch or compress the spring, the more energy is stored.

The amount of work done on a spring (which equals the elastic potential energy stored) can be calculated using the formula:

Work done, WW = Elastic potential energy stored

W=12kx2W = \frac{1}{2} k x^2

  • WW is work done (in joules, J)
  • kk is the spring constant (in newtons per metre, N/m)
  • xx is the extension or compression of the spring from its natural length (in metres, m)

This formula shows that the work done depends on both how stiff the spring is (spring constant) and how far it is stretched or compressed (extension).

For instance, if a spring with a spring constant of 200 N/m is stretched by 0.1 m, the work done on the spring is:

W=12×200×(0.1)2=0.5×200×0.01=1 JW = \frac{1}{2} \times 200 \times (0.1)^2 = 0.5 \times 200 \times 0.01 = 1 \text{ J}

PracticeExample 2

Worked Example

Example: Calculate the work done when a spring with a spring constant of 150 N/m is stretched by 0.2 m.

Hooke's Law and Extension

Hooke's Law states that the force needed to stretch or compress a spring is directly proportional to the extension or compression, as long as the spring is not stretched beyond its elastic limit.

Mathematically:

F=kxF = kx

  • FF is the force applied (in newtons, N)
  • kk is the spring constant (in newtons per metre, N/m)
  • xx is the extension or compression (in metres, m)

The spring constant kk measures the stiffness of the spring: a larger kk means a stiffer spring.

The limit of proportionality is the point beyond which Hooke's Law no longer applies. Beyond this limit, the spring will not return to its original length and may be permanently deformed.

A force-extension graph for a spring shows a straight line passing through the origin while Hooke's Law is obeyed. The gradient of this line is the spring constant kk.

  • Remember: Hooke's Law only applies up to the limit of proportionality.
  • The spring constant kk can be found from the gradient of the force-extension graph.

Elastic Potential Energy

Elastic potential energy is the energy stored in a spring (or any elastic object) when it is stretched or compressed.

The energy stored is equal to the work done to stretch or compress the spring.

On a force-extension graph, the elastic potential energy stored is represented by the area under the graph between zero extension and the current extension.

Since the force increases linearly with extension (Hooke's Law), the graph is a straight line and the area under it is a triangle. The area of this triangle is:

Area=12×base×height=12×x×F\text{Area} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times x \times F

Substituting F=kxF = kx, the energy stored is:

E=12kx2E = \frac{1}{2} k x^2

Energy is measured in joules (J).

For example, if a spring is stretched by 0.15 m and the force at this extension is 30 N, the elastic potential energy stored is:

E=12×0.15×30=2.25 JE = \frac{1}{2} \times 0.15 \times 30 = 2.25 \text{ J}

PracticeExample 6

Worked Example

Example: A spring is stretched by 0.12 m. The spring constant is 250 N/m. Calculate the elastic potential energy stored in the spring.

PracticeExample 7

Worked Example

Example: Calculate the work done in stretching a spring with a spring constant of 100 N/m by 0.25 m.

  • Work done on a spring is stored as elastic potential energy.
  • The formula W=12kx2W = \frac{1}{2} k x^2 applies only within the elastic limit of the spring.
  • The area under the force-extension graph represents the energy stored.

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