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AQA GCSE Physics

Revision Notes
(Stopping Distances)

Estimating Decelerating Forces

Estimating Decelerating Forces

Concept of Deceleration

Deceleration is the term used to describe a decrease in velocity over time. It is essentially acceleration in the opposite direction to the motion, so it is often called negative acceleration.

When a vehicle slows down, it experiences deceleration, which reduces its speed until it eventually stops. The size of the deceleration depends on the forces acting against the motion of the vehicle.

For example, if a car slows from 20 m/s to 0 m/s in 5 seconds, the deceleration is:

Deceleration=Change in velocityTime=0205=4 m/s2\text{Deceleration} = \frac{\text{Change in velocity}}{\text{Time}} = \frac{0 - 20}{5} = -4 \text{ m/s}^2

The negative sign shows the velocity is decreasing.

Forces Causing Deceleration

Several forces act to slow down a vehicle:

  • Friction between tyres and road: This is the main force that allows a vehicle to slow down safely. The roughness of the road surface and the condition of the tyres affect the size of this frictional force.
  • Braking force: When the driver applies the brakes, the brake pads press against the wheels, creating a force that opposes the motion and causes deceleration.
  • Air resistance: As the vehicle moves, air pushes against it, creating a force that slows it down. This force increases with speed but is usually smaller than friction and braking forces at typical road speeds.

Estimating Decelerating Force

The force causing deceleration can be estimated using Newton’s second law:

F=maF = ma

Where:

  • F is the decelerating force in newtons (N)
  • m is the mass of the vehicle in kilograms (kg)
  • a is the deceleration in metres per second squared (m/s²)

To find the average deceleration, you can use the initial speed and stopping distance with the equation:

v2=u2+2asv^2 = u^2 + 2as

Rearranged to find acceleration (or deceleration):

a=v2u22sa = \frac{v^2 - u^2}{2s}

Where:

  • uu = initial speed (m/s)
  • vv = final speed (m/s), usually 0 when stopping
  • ss = stopping distance (m)
  • aa = average deceleration (m/s²)

Once you have the deceleration, multiply by the vehicle’s mass to estimate the decelerating force. Note that the negative sign indicates the force acts opposite to the direction of motion; often, the size (magnitude) of the force is given as a positive value to describe its strength.

For instance, if a car of mass 1000 kg slows from 20 m/s to 0 over 40 m, the deceleration is:

a=022022×40=40080=5 m/s2a = \frac{0^2 - 20^2}{2 \times 40} = \frac{-400}{80} = -5 \text{ m/s}^2

Then the force is:

F=1000×(5)=5000 NF = 1000 \times (-5) = -5000 \text{ N}

The negative sign shows the force acts opposite to the motion, slowing the car down.

Quick calculation example: If a 500 kg bike slows down at 3 m/s², the decelerating force is F=500×3=1500F = 500 \times 3 = 1500 N.

Factors Affecting Decelerating Forces

The size of the decelerating force depends on several factors:

  • Road conditions: Wet, icy, or oily roads reduce friction between tyres and road, decreasing the maximum decelerating force and increasing stopping distance.
  • Vehicle condition: Worn tyres or faulty brakes reduce the braking force that can be applied safely, lowering deceleration.
  • Speed at the start of braking: Higher speeds require larger decelerating forces to stop in the same distance, or else the stopping distance increases.

Understanding these factors helps in estimating realistic decelerating forces in different driving conditions.

PracticeExample 2

Worked Example

Example: A 1500 kg car travelling at 25 m/s comes to a stop over a distance of 60 m. Calculate the average decelerating force acting on the car.

PracticeExample 3

Worked Example

Example: A vehicle of mass 1200 kg slows down at a rate of 4 m/s². Calculate the decelerating force acting on it.

PracticeExample 4

Worked Example

Example: A car travelling at 30 m/s stops in 75 m. The car’s mass is 1000 kg. Estimate the average decelerating force.

  • Remember that deceleration is just acceleration in the opposite direction, so always expect a negative value when calculating it.
  • Use the equation v2=u2+2asv^2 = u^2 + 2as to find acceleration or deceleration when you know speeds and stopping distance.
  • Friction and braking forces are the main causes of deceleration, but air resistance also plays a small role, especially at higher speeds.

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