Cambridge (CIE) IGCSE Physics

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(Electrical Quantities)

Electrical Power

Electrical Power

Electrical power tells us how quickly electrical energy is transferred. Think of it like the “speed” of delivering energy. A powerful kettle heats water faster because it transfers more energy each second.

Key ideas and equations

  • Definition: Power is the rate of energy transfer: P=EtP = \dfrac{E}{t}
  • Units: Power in watts (W), energy in joules (J), time in seconds (s). 1W=1J s11\,\text{W} = 1\,\text{J s}^{-1}.
  • From circuits: P=IVP = IV (current × voltage)
  • Using V=IRV=IR: P=I2RP = I^2 R and P=V2RP = \dfrac{V^2}{R}
  • Energy used over time: E=PtE = Pt and E=IVtE = IVt
  • Large appliances use kilowatts: 1kW=1000W1\,\text{kW} = 1000\,\text{W}
  • Billing unit: kilowatt-hour (kWh). 1kWh=3.6×106J1\,\text{kWh} = 3.6 \times 10^6\,\text{J}

Understanding the terms

  • Voltage (V): energy shifted per coulomb of charge. Higher voltage can push more energy per charge.
  • Current (I): rate of flow of charge. More charge per second means more energy moved each second.
  • Resistance (R): how much a component opposes current.

Worked Example

Worked example 1: Finding power and energy

A lamp runs at 12V12\,\text{V} and 2.0A2.0\,\text{A} for 5 minutes. Find its power and the energy used in joules and kWh.

Worked Example

Worked example 2: Cost of using an appliance

A 1.5kW1.5\,\text{kW} kettle runs for 4 minutes. Electricity costs 0.20 per kWh. Find the cost.

Tuity Tip

Hover me!

  • Power is “how fast” energy is transferred; energy is “how much.”
  • For a fixed resistor, doubling VV makes power four times bigger: P=V2RP = \dfrac{V^2}{R}.
  • kWh is a unit of energy, not power.
  • Choose a formula that matches what is given: use P=IVP=IV if you know II and VV; use I2RI^2R or V2/RV^2/R if resistance is involved.

Common misconceptions

  • “High voltage means high power.” Not always. Power depends on both II and VV: P=IVP=IV.
  • “kWh is a power.” It is energy used; bills charge per kWh.

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