Cambridge (CIE) IGCSE Physics

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(Earth & The Solar System)

Orbital Speed Equation

Orbital Speed Equation

Objects in nearly circular orbits (like planets and many satellites) move at an average speed that depends on how big the orbit is and how long one orbit takes. This is called average orbital speed.

The equation

Average orbital speed is given by

v=2πrTv = \frac{2\pi r}{T}

  • v = average orbital speed
  • r = average radius of the orbit (distance from the centre of the object being orbited)
  • T = orbital period (time for one full orbit)

Why this works

In one complete orbit the object travels the circumference of a circle, which is 2πr2\pi r. Speed is distance divided by time, so distance // time becomes 2πr/T2\pi r / T.

Units that match

  • Use metres (m) for rr and seconds (s) for TT to get vv in m/s.
  • If you use kilometres for rr, keep vv in km/s, or convert: 1 km = 1000 m.
  • Time conversions: 1 day = 86 400 s; 1 year ≈ 365 days.

Worked Example

Worked example: Earth orbiting the Sun

Given: r1.5×1011mr \approx 1.5\times10^{11}\,\text{m}, T=365daysT = 365\,\text{days}.

Common mistakes

  • Using πr2\pi r^2 (area) instead of 2πr2\pi r (circumference).
  • Using diameter instead of radius. Remember: radius is half the diameter.
  • Forgetting to convert days to seconds or km to m.
  • Thinking speed changes a lot in a circular orbit. In a circular orbit, speed is constant; in an elliptical orbit it varies, so v=2πr/Tv = 2\pi r/T gives an average value.

Real-world connections

  • Satellites closer to Earth (smaller rr) have shorter TT and must move faster to stay in orbit.
  • Outer planets have larger rr and much longer TT, so their average orbital speeds are lower.

Tuity Tip

Hover me!

Memory aid: “Circle distance over orbit time” → CDOT → v=2πr/Tv = 2\pi r / T.

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