WAEC WAEC Nigeria General Mathematics

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(Quadratic Equations)

Solution of Quadratic Equations: Using the Quadratic Formula

The Quadratic Formula

What is the Quadratic Formula?

The quadratic formula is a tool used to solve any quadratic equation of the form: ax2+bx+c=0ax^2 + bx + c = 0

It works even when factorising or completing the square seems tricky. The formula is: x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

 

Breaking It Down

  1. aa: The coefficient of x2x^2
  2. bb: The coefficient of xx
  3. cc: The constant (number without xx).
  4. ±\pm: This means there are two solutions, one for ++ and one for -

 

Understanding the Discriminant

The discriminant, b24acb^2 - 4ac, is key to predicting the nature of the roots:

  • If b24ac>0b^2 - 4ac > 0, the equation has two distinct real roots.
  • If b24ac=0b^2 - 4ac = 0, the equation has one real root (roots are equal).
  • If b24ac<0b^2 - 4ac < 0, the equation has two complex roots.

 

Steps to Solve Using the Quadratic Formula

  1. Write the equation in standard form: ax2+bx+c=0ax^2 + bx + c = 0

  2. Identify aa, bb and cc from the equation.
  3. Substitute aa, bb and cc into the quadratic formula: x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
  4. Simplify the discriminant (b24ac)(b^2 - 4ac).
  5. Calculate the two solutions by using ++ and - for the ±\pm symbol.
  6. Simplify the final answers.

 

Examples

Solve x2+6x+5=0x^2 + 6x + 5 = 0

  1. Identify coefficients: a=1,b=6,c=5a = 1, b = 6, c = 5
  2. Substitute into the formula: x=6±624(1)(5)2(1)x = \frac{-6 \pm \sqrt{6^2 - 4(1)(5)}}{2(1)}
  3. Simplify the discriminant: x=6±36202x = \frac{-6 \pm \sqrt{36 - 20}}{2}
  4. Simplify further: x=6±162x = \frac{-6 \pm \sqrt{16}}{2}
  5. Find the two solutions:

    • For ++: x=6+42=1x = \frac{-6 + 4}{2} = -1
    • For -: x=642=5x = \frac{-6 - 4}{2} = -5

Solution: x=1orx=5x = -1 \quad \text{or} \quad x = -5

 

 

 

Worked Example

Solve 4x2+12x+9=04x^2 + 12x + 9 = 0

 

 

 

Tuity Tip

Hover me!

 

Always simplify the discriminant b24acb^2 - 4ac first—it’s the key to knowing how many solutions there are.

Don’t forge ±\pm: You’re solving for two values of xx

Double-check your substitutions—small errors with negatives can lead to the wrong answer

 

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