WAEC WAEC Nigeria General Mathematics

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(Areas)

Area of Polygons

Area

 

What is Area?

Area is the amount of space enclosed within the perimeter of a 2D shape.

It is measured in square units such as mm2mm^2, cm2cm^2, m2m^2, or km2km^2.

Example: The area of a sports field or a painting.

 

How to Find the Area of a Shape on a Square Grid

  1. Count the total number of whole squares inside the shape.

  2. Pair up half squares to form whole squares.

  3. Use the given scale to determine how much area one square represents.

  4. Multiply the number of squares counted by this value to find the total area.

 

Key Area Formulae:

Area of a Rectangle: A=l×wA = l \times w

 
area of a rectangle
 

where:

  • l = length

  • w = width

 

Area of a Triangle: A=12bhA = \frac{1}{2}bh

 
area of a triangle
 

where:

  • b = base

  • h = perpendicular height

 

Area of a Triangle Using Sine

To find the area of any triangle (not just right-angled), use:

Area=12absinC\text{Area} = \frac{1}{2} ab \sin C

 

sine rule for calculating area of a triangle

 

Where:

  • aa and bb are two sides
  • CC is the included angle

When to Use This Formula

You know two sides and the angle between them

It avoids having to use height directly

 

Worked Example: Area of a Triangle

In triangle DEF:

DE=5.2mDE = 5.2 m

EF=7.1mEF = 7.1 m

D=64°\angle D = 64\degree

 

diagram of triangle for question

 

Calculate the Area

Area=125.27.1sin(64)\text{Area} = \frac{1}{2} \cdot 5.2 \cdot 7.1 \cdot \sin(64^\circ)

Area0.55.27.10.898816.6 m2 (3 s.f.)\text{Area} \approx 0.5 \cdot 5.2 \cdot 7.1 \cdot 0.8988 \approx 16.6 \text{ m}^2 \text{ (3 s.f.)}

 

 

Area of a Trapezium: A=12(a+b)hA = \frac{1}{2}(a + b)h

 
Area of a trapezium
 

where:

  • a and b = lengths of the parallel sides

  • h = perpendicular height

 

Area of a Parallelogram: A=bhA = bh

 
area of parallelogram
 

where:

  • b = base

  • h = perpendicular height (not the side length)

 

Examples

Example 1: Area of a Trapezium

  • Given: a = 26 cm, b = 11 cm, h = 9 cm

 

diagram of trapezium for example question

 

A=12(26+11)×9A = \frac{1}{2}(26 + 11) \times 9

A=12(37)×9A = \frac{1}{2}(37) \times 9

A=333cm2A = 333 cm^2

 

Final Answer: 333 cm2cm^2

 

Example 2: Area of a Parallelogram

  • Given: b = 20 cm, h = 18 cm

 

diagram of parallelogram for example

 

A=20×18A = 20 \times 18

A=360cm2A = 360 cm^2

 

Final Answer: 360 cm2cm^2

 

Example 3: Area of a Isosceles triangle

  • Given: b = 14 cm, h = 6 cm

 

isosceles triangle example area question

 

A=12×13×6A = \frac{1}{2} \times 13 \times 6

A=39cm2A = 39 cm^2

 

Final Answer: 39 cm2cm^2

 

 

Tuity Tip

Hover me!

Find missing lengths first—you may need to use Pythagoras' Theorem or other properties of shapes.

Label all given dimensions clearly—ensure you are using the correct base and height.

For trapeziums and parallelograms, check the perpendicular height, not the slant height.

Check your units carefully—make sure all dimensions are in the same units before calculating.

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