WAEC WAEC Nigeria General Mathematics

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(Sequence and Series)

Arithmetic and Geometric Progression

Arithmetic and Geometric Progression

 

Defining Arithmetic Progression

An arithmetic progression is a progression of numbers in which each term after the first is obtained by adding a constant value, called the common difference (dd), to the preceding term. The progression can be expressed as:

  • aa, a+da + d, a+2da + 2d, a+3da + 3d, ..., a+(n1)da + (n-1)d

where aa is the first term, dd is the common difference, and nn represents the position of a term within the progression.

Key Characteristics

  • Linear Growth: Arithmetic progressions grow linearly, as depicted by their evenly spaced points when plotted on a graph.
  • Uniform Difference: The difference between consecutive terms remains constant throughout the progression.

 

Calculating Terms in an Arithmetic Progression

The nnth term of an arithmetic progression can be calculated using the formula:

an=a+(n1)da_n = a + (n - 1)d

This formula helps determine any term's value based on its position (nn) within the progression.

 

Example: Finding a Specific Term

Given that the first term of a progression (aa) is 4 and the common difference (dd) is 3, find the 5th term (a5a_5).

Substituting into the formula, we get a5=4+(51)×3=4+12=16a_5 = 4 + (5 - 1)\times3 = 4 + 12 = 16.

 

Worked Example

Worked Example: Term Calculation

An arithmetic progression has a first term of 5 and a common difference of -2. Calculate the 8th term.

 

a8=5+(81)(2)=514=9a_8 = 5 + (8 - 1)(-2) = 5 - 14 = -9.
 

 

Tuity Tip

Hover me!

To quickly find the sum of an arithmetic progression, use the formula for the sum of the first nn terms: Sn=n2[2a+(n1)d]S_n = \frac{n}{2}[2a + (n-1)d].

Familiarize yourself with various arithmetic progression problems, as they often appear in standardized tests and real-world scenarios.

 

 

 

 

Geometric progressions

A geometric progression is a progression where each term is found by multiplying the previous term by a constant number called the common ratio, rr.

General Formula: an=a1r˙(n1)a_n = a_1 \dot r^(n-1)

 

where:

  • a1a_1 is the first term,
  • rr is the common ratio,
  • nn is the position of the term 

 

Example:

Find the first 5 terms of the geometric progression where a1=3a_1 = 3 and r=2r = 2

Solution: 3,6,12,24,48,...3, 6, 12, 24, 48, ...

 

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